There exists a syntax to get the address of the member function in MSVC (starting from MSVC 2005 IMHO). But it's pretty tricky. Moreover, the obtained pointer is impossible to cast to other pointer type by conventional means. Though there exists a way to do this nevertheless.
Here's the example:
// class declaration
class MyClass
{
public:
void Func();
void Func(int a, int b);
};
// get the pointer to the member function
void (__thiscall MyClass::* pFunc)(int, int) = &MyClass::Func;
// naive pointer cast
void* pPtr = (void*) pFunc; // oops! this doesn't compile!
// another try
void* pPtr = reinterpret_cast<void*>(pFunc); // Damn! Still doesn't compile (why?!)
// tricky cast
void* pPtr = (void*&) pFunc; // this works
The fact that conventional cast doesn't work, even with
reinterpret_cast probably means that MS doesn't recommend this casting very strongly.
Nevertheless you may do this. Of course this is all implementation-dependent, you must know the appropriate calling convention to do the thunking + have appropriate assembler skills.
or
4
try this. should let you cast anything to anything :)
template<typename OUT, typename IN>
OUT ForceCast( IN in )
{
union
{
IN in;
OUT out;
}
u = { in };
return u.out;
};
then
void* member_address = ForceCast<void*>(&SomeClass::SomeMethod);
